16-1/4p^2=0

Solution for 16-1/4p^2=0 equation:

16-1/4p^2=0


Domain of the equation: 4p^2!=0

p^2!=0/4

p^2!=√0

p!=0

p∈R


We multiply all the terms by the denominator


16*4p^2-1=0

Wy multiply elements

64p^2-1=0

a = 64; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·64·(-1)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*64}=\frac{-16}{128}
=-1/8
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*64}=\frac{16}{128}
=1/8
$